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Calculate the EMF of the cell,
$\begin{array}{l} Mg / {Mg}^{2 +} (1 M) / / {Cu}^{2 +} (1 M) / Cu \\ (Given E_{{Mg}^{2 +} / Mg}^{0} = - 2.37 V; E_{{Cu}^{2 +} / Cu}^{0} = + 0.34 V;) \end{array}$

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–2.71 V

+2.71 V

+2.03 V

–2.03 V

answer is A.

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Detailed Solution

$E_{Cell}^{0} = E_{Cu}^{0} - E_{Mg}^{0} = 0.34 - (- 2.37)$

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