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Q.

Calculate the energy emitted when electrons of 2.0 g atom of hydrogen undergo transition giving the spectral lines of lowest energy in the visible region of its atomic spectra.

RH=1.1×107m1;C=3×108m/sec;h=6.625×1034J.sec

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a

182.5KJ

b

365KJ

c

91.25KJ

d

18.25KJ

answer is B.

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Detailed Solution

1λ=RH[1n121n22]n1=2n2=3 λ=6.55×107m    E=hcλ.6.625×1034×3×1086.55×107=3.03×10195 Energy released  =E×N    =3.03×1019×6.023×1023×2 =365KJ

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