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Calculate the energy in joule corresponding to light of wavelength 45 nm. (Planck's constant, h = 6.63 × $10^{- 34}$ Js , speed of light, c = 3 ×10⁸ ms^-1)

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$6.67 \times 10^{15}$

$6.67 \times 10^{11}$

$4.42 \times 10^{- 15}$

$4.42 \times 10^{- 18}$

answer is D.

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Detailed Solution

$E = \frac{hc}{λ} [Given, λ = 45 nm = 45 \times 10^{- 9} m]$

Putting the given values in the above equation

$E = \frac{6.63 \times 10^{- 34} \times 3 \times 10^{8}}{45 \times 10^{- 9}} = 4.42 \times 10^{- 18} J$

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