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Q.

Calculate the focal length of a lens whose refractive index and radius of curvature of each surfaces are 1.50, 30 cm and -35 cm respectively

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a

82.30 cm

b

28.56 cm

c

52.80 cm

d

32.36 cm

answer is D.

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Detailed Solution

1f=(μ1)1R11R2 =(1.501)130+1351f=0.5×(0.0333+0.0285)=0.5×0.0618=0.0309f=10.0309=32.36cm

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