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Calculate the kinetic energy of one mole of argon at 127^oC.
Given, Boltzmann’s constant, k_B = 1.381 x 10^-23 J molecule^-1 K^-1. Avagadro’s number, N = 6.02 x 10²³mol^-1.

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238 J

1000 J

2000 J

4988.2 J

answer is B.

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Detailed Solution

Here T = 127 + 273 = 400K
N = 6.02 x 10²³mol^-1, k_B = 1.381 x 10²³ J molecule^-1 K^-1
Kinetic energy of one mole of gas,
= 4988.2 J

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