Calculate the mass of ammonia that can be produced from the decomposition of a sample of ${\left({\mathrm{NH}}_4\right)}_2{\mathrm{PtCI}}_6$ containing 0.100 g Pt.

mole of ${\left({\mathrm{NH}}_4\right)}_2{\mathrm{PtCI}}_6$= mole of Pt

$=\frac{0.1}{195}$

${\left({\mathrm{NH}}_4\right)}_2{\mathrm{PtCl}}_6⟶{\mathrm{NH}}_3$

POAC on N atom 

mole of N atom in ${\left({\mathrm{NH}}_4\right)}_2{\mathrm{PtCI}}_6$= mole of N atom in ${\mathrm{NH}}_3$

$2\times$mole of ${\left({\mathrm{NH}}_4\right)}_2{\mathrm{PtCI}}_6$= mole of ${\mathrm{NH}}_3$

$2\times \frac{0.1}{195}=\frac{\text{Wt.of }{\mathrm{NH}}_3}{17}$

$=\frac{0.1}{195}\times 2\times 17$

$=0.0175 \mathrm{g}$