Calculate the mass of CaO required to remove the hardness of 106 litre of water containing 1.62 gm of calcium bicarbonate per litre

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Calculate the mass of CaO required to remove the hardness of $10^{6}$ litre of water containing 1.62 gm of calcium bicarbonate per litre

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$5.6 \times 10^{5} g m$

$15.6 \times 10^{5} g m$

$0.56 \times 10^{15} g m$

$156 \times 10^{5} g m$

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Detailed Solution

$C a O + C a {(H C O_{3})}_{2} \to_{}^{} 2 C a C O_{3} + H_{2} O$

$∴$ Equivalent Wt. of $C a {(H C O_{3})}_{2}$ present in hard water (1 litre) $\frac{1.62}{162 / 2} = 0.02$

$∴$ Equivalent Wt. of CaO required to remove $C a {(H C O_{3})}_{2}$ in 1 litre = 0.02

$∴$ Equivalent Wt. of CaO required to remove $C a {(H C O_{3})}_{2}$ in $10^{6}$ litre $= 0.02 \times 10^{6}$

$∴$ mass of $C a O = 0.02 \times 10^{6} \times \frac{56}{2} g = 5.6 \times 10^{5} g m$

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