Calculate the mass percent (w/w) of sulphuric acid in a solution prepared by dissolving 4g of sulphur trioxide in a 100ml of sulphuric acid solution containing 80 mass percent (w/w) of $H_{2} {SO}_{4}$ and heving a density of $1.96 g / ml$ .
(Molecular weight of $H_{2} {SO}_{4} = 98 gm$ )
Take reaction ${SO}_{3} + H_{2} O ⟶ H_{2} {SO}_{4}$

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$41.65 %$

$84 %$

$80.85 %$

None of these

answer is A.

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Detailed Solution

Mass of $H_{2} {SO}_{4}$ $100 \times 1.96 \times \frac{80}{100} =$ $156.8 g$

$[\frac{\frac{4}{80} \times 98 + 156.8}{100 \times 1.96 + 4}] \times 100 = 80.85 %$

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