Calculate the milliequivalents of $\mathrm{HCl}$ in its $3.65 \mathrm{g}$ (at.

wt., $\mathrm{H} = 1, \mathrm{Cl} = 35.5)$

$1 \mathrm{mol} \mathrm{HCl}=1\mathrm{mol} {\mathrm{H}}^{+}\text{ions. }$ So, eq. wt. of

$\mathrm{HCl}=\text{ mol }$wt. of $\mathrm{HCl}=1+35.5=36.5$

$\therefore$  Milliequivalents of

$\begin{array}{r}\mathrm{HCl}=(\text{ wt. }/\text{ eq. wt. })\times 1000\\ =(3.65/36.5)\times 1000=100.\end{array}$