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Q.

Calculate the molal depression constant of a solvent which has freezing point 16.6oC and latent heat of fusion 180.75 Jg-1.

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a

2.8616

b

2.68

c

4.68

d

3.86

answer is B.

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Detailed Solution

Kf=RTf21000×Lf,R=8.314JK−1mol−1 Tf=273+16.6=289.6K;Lf=180.75Jg−1Kf=8.314×289.6×289.61000×180.75=3.86

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