Calculate the molar conductivity of 0.2 mol L^-1 KCl solution.

$\begin{array}{l}\text{ Concentration }=0.2\mathrm{mol} {\mathrm{L}}^{-1}\\ =1000\times 0.2 \mathrm{mol} {\mathrm{m}}^{-3}=200 \mathrm{mol} {\mathrm{m}}^{-3}\end{array}$
$\begin{array}{l}\text{ Molar conductivity }={\mathrm{\Lambda }}_{\mathrm{m}}=\frac{\mathrm{\kappa }}{\mathrm{C}}\\ =\frac{248\times {10}^{-3}{\mathrm{Sm}}^{-1}}{200{\mathrm{molm}}^{-3}}\\ =124\times {10}^{-5}{\mathrm{Sm}}^2{\mathrm{mol}}^{-1}\end{array}$