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Q.

Calculate the molecular weight of a substance whose 7.0% by mass solution in water freezes at -0.93^oC. The cryoscopic constant of water is 1.86^oC kg mol^-1:

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a

$160 g {mol}^{- 1}$

b

$155 g {mol}^{- 1}$

c

$140 g {mol}^{- 1}$

d

$150 .5 g {mol}^{- 1}$

answer is B.

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Detailed Solution

$\begin{aligned} 0 .93 = 1 .86 \times [\frac{7 / x}{93 / 1000}] \\ x = 150 .5 g {mol}^{- 1} \end{aligned}$

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