Calculate the percent ionic character in Br-Cl, if the electronegativity values of Br and Cl are 2.8 and 3.0 respectively.

Percentage of ionic character of Br-Cl is determined using the respective formula:

$\mathrm{Percentage} \mathrm{of} \mathrm{ionic} \mathrm{character}=16\left({\chi }_{\mathrm{Cl}}-{\chi }_{\mathrm{Br}}\right)+3.5{({\chi }_{\mathrm{Cl}}-{\chi }_{\mathrm{Br}})}^2$

Here, ${\chi }_{\mathrm{Br}} \mathrm{and} {\chi }_{\mathrm{Cl}}$ are electronegativities of Br and Cl respectively. Calculation for determining the ionic character in Br-Cl bond is:

$\begin{array}{ccc}\mathrm{Percentage} \mathrm{of} \mathrm{ionic} \mathrm{character}& =& 16(3.0-2.8)+3.5{(3.0-2.8)}^2\\ & =& 16(0.2)+3.5(0.04)\\ & =& 3.34\end{array}$