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Q.

Calculate the percentage degree of dissociation of an electrolyte XY₂ (Normal molar mass = 164) in water if the observed molar mass by measuring elevation in boiling point is 65.6:

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a

75%

b

25%

c

65%

d

None of these

answer is A.

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Detailed Solution

$\begin{array}{cccc} {XY}_{2} & ⇌ & X^{2 +} & + & 2 Y^{-} \\ Initially & 1 & 0 & 0 \\ at equilibrium & 1 - α & α & 2 α \end{array}$
Total no. of moles = $1 - α + α + 2 α = 1 + 2 α$
$\begin{array}{l} i = \frac{Normal molar mass}{Observed molar mass}; \frac{1 + 2 α}{1} = \frac{164}{65.6} \\ ∴ α = 0 .75; % α = 75 % \end{array}$

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Calculate the percentage degree of dissociation of an electrolyte XY2 (Normal molar mass = 164) in water if the observed molar mass by measuring elevation in boiling point is 65.6: