Q.

Calculate the percentage loss (nearest integral value) in the mass, when 2.02 x 102gm KNO3 i completely decomposed by heating into KNO2(s) and O2(g)

KNO3(s)KNO2(s)+O2(g)

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answer is 16.

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Detailed Solution

O2202×100=%

KNO3ΔKNO2+12O2

202101×12×32Wt.O2 obtained 202×100

%=202101×12×32202×10016

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