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Q.

Calculate the PH  of 0.08 M solution of hypochlorous acid  (HOCl) . The ionization constant of the acid is  2.5×105 . (Consider 0.08x=0.08   and log(1.41)=0.15  )

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a

6.5

b

2.80

c

2.85  

d

11.15

answer is B.

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Detailed Solution

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ka=x20.08x=2.5×105 x=1.41×103=[H+] PH=log(1.41×103)=2.85

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