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Q.

Calculate the $p H$ at which $M g {(O H)}_{2}$ will just begin to precipitate from a $0.100 M$ $M g {(N O_{3})}_{2}$ solution by addition $N a O H .$ of Given: $K_{S P} o f M g {(O H)}_{2} = 1.0 \times 10^{- 11}$

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a

5

b

9

c

6

d

8

answer is B.

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Detailed Solution

$\begin{array}{l} Mg (OH)_{2} ⇌ {Mg}^{2 +} (aq) + 2 {OH}^{-} (aq) \\ Ionic product = [{Mg}^{2 +}] {[{OH}^{- 1}]}^{2} = K_{sp} \\ \Rightarrow 0.1 \times x^{2} = 1 \times 10^{- 11} \\ \Rightarrow x^{2} = 1 \times 10^{- 11} \\ \Rightarrow x = 1 \times 10^{- 5} \\ \Rightarrow pOH = 5 \\ ∴ pH = 9 \end{array}$

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