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Q.

Calculate the quantity of electricity that would be required to receive 12.3 g of nitrobenzene to aniline. If the current efficiency for the process is 50 per cent. If the potential drop across the cell is 3.0 volts. How much energy will be consumed in KJ? (If the answer is x then x-340 is)

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answer is 7.

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Detailed Solution

C₆H₅NO₂ = 6H⁺ + 6e^- → C₆H₅NH₂ +2H₂O
$Eq . wt = \frac{M \cdot wt}{6} = \frac{123}{6} w = \frac{Eit}{96500} \Rightarrow 12.3 = \frac{12.3 \times i \times t \times 50}{6 \times 96500 \times 100} = 115800 x 3 = 347 kJ 347 kJ - 340 kJ = 7 kJ$

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