Calculate the ratio of rate of effusion of $O_{2}$ and $H_{2}$ from a container containing $16 gm$ $O_{2}$ and $2 gm H_{2} :$

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$1 : 4$

$8 : 1$

$4 : 1$

$1 : 8$

answer is A.

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Detailed Solution

$\frac{r_{O_{2}}}{r_{H_{2}}} = \frac{n_{O_{2}}}{n_{H_{2}}} \times \sqrt{\frac{M_{H_{2}}}{M_{O_{2}}}} = \frac{16 \times 2}{32 \times 2} \sqrt{\frac{2}{32}} = \frac{1}{2} \times \frac{1}{4} = \frac{1}{8}$

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