Q.

Calculate the resonance energy of N2O from the following data; ΔHf of N2O=82 kJ/mol . Bond energies of NN,O=O,N=N and N=O bonds are 946, 498, 418 and 607 kJ/mol respectively.

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a

-88 kJ/mol

b

-170 kJ/mol

c

-82 kJ/mol

d

-258 kJ/mol

answer is A.

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Detailed Solution

NN+12O=ON=N=O

ΔHf0=BE of reactants -BE of products 

=BE(NN)+12BE(O=O)-[BE(N=N)+BE(N=O)]

=946+12×498-(418+607)=170kJ

 Resonance energy =ΔHfo   (observed) -ΔHfo

(cal.)=82-170=-88kJ/mol

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