Calculate the spin only magnetic moment of Ti3+ ion (Atomic number of Ti = 22).

µ = n(n+2)n(n+2) n = 1 µ = 1(1+2) µ =3 =1.732

Calculate the spin only magnetic moment of Ti3+ ion (Atomic number of Ti = 22).

µ = n(n+2)n(n+2) n = 1 µ = 1(1+2) µ =3 =1.732

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Calculate the spin only magnetic moment of Ti³⁺ ion (Atomic number of Ti = 22).

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1.732

$\sqrt{3}$

both a and c

$\sqrt{4}$

answer is D.

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µ = $\sqrt{n (n + 2)}$

$\sqrt{n (n + 2)}$

n = 1

µ = $\sqrt{1 (1 + 2)}$

µ = $\sqrt{3}$ =1.732

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Calculate the spin only magnetic moment of Ti3+ ion (Atomic number of Ti = 22).

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Calculate the spin only magnetic moment of Ti³⁺ ion (Atomic number of Ti = 22).