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Q.

Calculate the steady state current in the $2 Ω$ resistor shown in the circuit. The internal resistance of the battery is negligible, and the capacitance of the condenser ‘C’ is $0.2 μ F$ .
(Round off to nearest integer)

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Detailed Solution

In steady state current through capacitor is zero.

Reff $= \frac{2 \times 3}{2 + 3} + 2.8 = 4 Ω$

$i = \frac{V}{R} = \frac{6}{4} = \frac{3}{2} A$

Current through $2 Ω$ resistance $0.9 A$

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