Calculate the sum of Retardation factor values for both compounds A and B from the following date 

$\begin{array}{l}{\left(Rf\right)}_A=\frac{\text{distance\hspace{0.17em}\hspace{0.17em}travelled\hspace{0.17em}by\hspace{0.17em}A}}{\text{distance\hspace{0.17em}travelled\hspace{0.17em}solvent\hspace{0.17em}}}=\frac{1}{3}\\ {\left(Rf\right)}_B=\frac{\text{distance\hspace{0.17em}\hspace{0.17em}travelled\hspace{0.17em}by\hspace{0.17em}A}}{\text{distance\hspace{0.17em}travelled\hspace{0.17em}solvent\hspace{0.17em}}}=\frac{2}{3}\end{array}$

$\therefore total=\frac{1}{3}+\frac{2}{3}=1$