Calculate the surface area of a catalyst that adsorbs 10³cm³ of N₂ (reduced to STP) per gram in order to form the monolayer. The effective area occupied by N₂ molecule on the surface is 1.6 × 10^–15cm²

Number of N₂​ molecules  =

 $$\begin{gathered} \frac{\mathrm{Volume} \mathrm{at} \mathrm{STP}(\mathrm{in} \mathrm{ml})}{\mathrm{Volume}\left(\mathrm{ml}\right)\times {\mathrm{N}}_{\mathrm{A}}}=\frac{{10}^3\times 6.023\times {10}^{23}}{22400} \\ =2.69\times {10}^{22} \end{gathered}$$

Total area covered by N₂​= 2.69×10²²×1.62×10⁻¹⁵ =435.5×10⁵cm²=4355 m².