Calculate the total number of electrons present in one mole of methane (CH₄).

The answer is : $6.023\times {10}^{\mathrm{x}}\text{ electrons. }$

Determine the value of x.

One molecule of methane contains 10 electrons: 6 from carbon and one from each hydrogen.

$$\begin{gathered} 1 \mathrm{mole} \mathrm{of} {\mathrm{CH}}_4=6.023\times {10}^{23} {\mathrm{CH}}_4 \mathrm{molecule} \\ 6.023\times {10}^{23} {\mathrm{CH}}_4\mathrm{e} \mathrm{molecules}=10\times 6.023\times {10}^{23} {\mathrm{CH}}_4 \mathrm{molecules} \\ =6.023\times {10}^{24} \mathrm{electrons} \end{gathered}$$