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Calculate the value of R, if the maximum value of forward current of the diode is 100 mA, when diode is Ge (barrier potential = 0.3V)

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10 $Ω$

9 $Ω$

8 $Ω$

12 $Ω$

answer is A.

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Detailed Solution

$\begin{array}{rcl} \begin{matrix} V = V_{diode} + V_{Resistance} \\ = 0.3 + I \times R_{R} \\ = 0.3 + R \times 100 \times 10^{- 3} \end{matrix} \\ \Rightarrow & 1.5 = 0.3 + R \times 0.1 \\ \Rightarrow & R = 12 Ω \end{array}$

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