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Calculate the value of R, if the maximum value of forward current of the diode is 100 mA, when diode is Ge(barrier potential =0.3V)

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$12 Ω$

$9 Ω$

$10 Ω$

$8 Ω$

answer is A.

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Detailed Solution

$V = I R R = \frac{V}{I} = \frac{1.5 - 0.3}{100 \times 10^{- 3}} = \frac{1.2}{0.1} = 12 Ω$

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