Calculate the vapour pressure of an aqueous solution of 1.0 molal glucose solution at 100°C.

$\frac{p_0-p_s}{p_0}=\frac{n_1}{n_1+n_2}$

$\frac{p_0-p_s}{p_0}=\frac{n_1}{n_2}$

$=\frac{W_{solute}}{M_{solute}}\times \frac{1000}{W_{solvent}}\times \frac{M_{solvent}}{1000}$

$=m\times \frac{M_{solvent}}{1000}$

$\frac{760-p}{760}=1\times \frac{18}{1000}$

=746.32 mm of Hg