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Calculate the volume of a frustum of a cone given below: (Use $π$ = 3.14)

R = 36 ft, r = 24 ft, h = 150 ft.

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419,552

f t^{3}

439,552

f t^{3}

449,552

f t^{3}

429,552

f t^{3}

answer is D.

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Detailed Solution

Given R = 36 ft, r = 24 ft, h = 150 ft.
Volume of the frustum cone is

V = \frac{π h}{3} (R^{2} + Rr + r^{2})

\Rightarrow V = \frac{(3.14 \times 150)}{(3)} [36^{2} + 36 \times 24 + 24^{2}]

\Rightarrow V = 3.14 \times 50 [1, 296 + 864 + 576]

\Rightarrow V = 157 [2, 736]

\Rightarrow V = 429, 552 f t^{3}

Therefore, volume of a frustum cone is

429, 552 f t^{3}

.
Hence, the correct option is 4.

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