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Calculate the volume strength and Normality of $1.7 % (W / v) H_{2} O_{2}$ solution

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4.6 volume 1N

5.6 Volume 1N

2.3 Volume 1N

5.6 Volume 0.5 N

answer is C.

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Detailed Solution

$3 % (w / v)$ solution has a volume strength of 100

Volume strength of $1.7 % (w / v) = \frac{1.7 \times 100}{30} = 5.6 v o l u m e$

17g of $H_{2} O_{2}$ present in 1000ml solution is 1 normal

Normality of 1.7g of $H_{2} O_{2}$ present in $100 m l = \frac{1.7 \times 1000}{17 \times 100} = 1 N$

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