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Calculate the weight of lime (CaO) obtained by heating 200 kg of 95% pure limestone (CaCO₃) :

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104.4 kg

105.4 kg

212.8 kg

106.4 kg

answer is D.

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Detailed Solution

Mass of pure ${CaCO}_{3} = 200 \times \frac{95}{100} = 190 kg$
$\begin{array}{cl} {CaCO}_{3} \overset{∆}{\to} & CaO + {CO}_{2} \\ 100 g & 56 \\ 1 g & \frac{56}{100} \\ 190 kg & \frac{56}{100} \times 190 kg = 106 .4 kg \end{array}$

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