Calculate the weight of lime (CaO) obtained by heating 200 kg of 95% pure lime stone $\left({\mathrm{CaCO}}_3\right).$

 $\begin{array}{l}{\mathrm{CaCO}}_3\stackrel{ }{\to }\mathrm{CaO}+{\mathrm{CO}}_2\\ 100\mathrm{g} 56\mathrm{g} 44\mathrm{g}\\ 100\mathrm{g}{\mathrm{CaCO}}_3\mathrm{give}=56\mathrm{g}\mathrm{CaO}\\ 1\mathrm{g}{\mathrm{CaCO}}_3\mathrm{give}=\frac{56}{100}\mathrm{g}\mathrm{CaO}\\ 200\times \frac{95}{100}{\text{×10}}^3\mathrm{g}{\mathrm{CaCO}}_3\mathrm{give}=\frac{56}{100}\times \frac{200\times 95}{100}{\text{×10}}^3{\text{g\hspace{0.17em}=1064×10}}^2\text{g=\hspace{0.17em}}106.4\mathrm{kg}\end{array}$

(200Kg of 95% ${\mathrm{CaCO}}_3$=$200\times \frac{95}{100}\mathrm{Kg}$ = $\frac{200\times 95}{100}\times {10}^3\mathrm{g}$)