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Q.

Calculate the work done when $1 mol$ of an ideal gas is compressed reversibly from 1 bar to constant temperature of $300 K$

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a

$4.01 kJ$

b

$18.02 kJ$

c

$- 14.01 kj$

d

$3.458 kj$

answer is B.

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Detailed Solution

$Work done = - 2.303 n R T \log \frac{P_{1}}{P_{2}} = - 2.303 \times 8.314 \times 300 \log \frac{1}{4} = 3458.3 J = 3.458 kJ$

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