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Calculate the work required to stop a car of mass $1500 kg$ moving at a speed of $60 km / h$ ?

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20.83 kJ

208.3 kJ

2083 kJ

2.083 kJ

answer is B.

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Detailed Solution

The work required to stop the car is

208.3 kJ

The kinetic energy of the car is zero as it stops. So, the work that is required to stop the car will be equal to its kinetic energy.
Mass of the car,

m = 1500 kg

Velocity of car,

v = 60 km / h

= 60 \times \frac{1000 m}{60 \times 60 s}

= \frac{50}{3} m / s

The work done required to bring the object to rest will be equal to the kinetic energy of the body, which is equal to

W = \frac{1}{2} m v^{2}

\Rightarrow W = \frac{1}{2} \times 1500 \times (\frac{50}{3}) \times (\frac{50}{3})

\Rightarrow W = \frac{2500}{2} \times 1500 \times 3 \times 3

\Rightarrow W = 208333.3 J

The kinetic energy of the car when it comes to rest

= 0 J

Work done on object = change in kinetic energy

= 208333.3 - 0 J

= 208333.3 J

Convert joule into kilojoule by divide the given joule value by

1000

= \frac{208333.3 J}{1000}

= 208.3 kJ

Hence, the work required to stop the car is

208.3 kJ

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