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Calculate value of $\frac{X + Y + Z}{10}$ , here X is $O - N - O$ bond angle in $N O_{3}^{-}, Y$ is $O - N - O$ bond angle in $N O_{2}^{+}$ and Z is $F - X e - F$ adjacent bond angle in $X e F_{4}$ .

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answer is 39.

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Detailed Solution

$X = 120 (s p^{2} -$ hybridization)
$Y = 180$ (sp-bridization)
$Z = 90 (s p^{3} d^{2} -$ hybridizatiuon)

$\frac{120 + 180 + 90}{10} = \frac{390}{10} = 39$

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