Calculate value of $\frac{X + Y + Z}{10}$ , here X is O- N -O bond angle in ${NO}_{3}^{-}, Y is O - N - O$ bond angle in ${NO}_{2}^{+} and Z is F - Xe - F$ adjacent bond angle in XeF₄

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answer is 39.

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Detailed Solution

$\begin{array}{l} X = 120 ({sp}^{2} - hybridisation) Y = 180 (sp - hybridisation) \\ Z = 90 ({sp}^{3} d^{2} - hybridisation) \frac{120 + 180 + 90}{10} = \frac{390}{10} = 39 \end{array}$

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