Calculate Vrms of O2 at 273K and 1×105 Pa Pressure is ___________ ms−1(The density of O2 under these condition is 1.42kg/m3 )

Vrms=3Pd=3×1051.42=460m/sAlso Vrms=3RTM=3×8.314×27332×10−3=461.28m/s

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

Calculate $V_{r m s}$ of $O_{2}$ at 273K and $1 \times 10^{5}$ Pa Pressure is ___________ $m s^{- 1}$
(The density of $O_{2}$ under these condition is $1.42 k g / m^{3}$ )

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 458.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

$V_{r m s} = \sqrt{\frac{3 P}{d}} = \sqrt{\frac{3 \times 10^{5}}{1.42}} = 460 m / s$

$A l s o V_{r m s} = \sqrt{\frac{3 R T}{M}} = \sqrt{\frac{3 \times 8.314 \times 273}{32 \times 10^{- 3}}} = 461.28 m / s$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE