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Q.

Calculate work done in kJ in chemical reaction $A (s) + 3 B (g) \to C (l) at 227^{\circ} c$ at 1 atm in closed vessel

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answer is 12.

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Detailed Solution

Work done in chemical reaction, $W = - Δng \cdot RT$
$∆ n_{g} = 0 - 3 = - 3; W = \frac{(- 3) \times 8 .314 \times 500}{1000} = 12 .471 KJ = 12$

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Calculate work done in kJ in chemical reaction A(s)+3B(g)→C(l) at 227∘c at 1 atm in closed vessel