Q.

Calculate ΔrG for  NH4Cl,s  at 310K

Given: ΔrHNH4Cl,s=314.5kJ/mol; ΔrCp=0

SN2(g)=192JK1mol1; SH2(g)=130.5JK1mol1;SCl2(g)=233JK1mol1;SNH4Cl(s)=99.5JK1mol1

All given data at 300 K.

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a

-202.3 kJ/mol

b

-426. 7 kJ/mol

c

-198.56 kJ/mol

d

None of these

answer is A.

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Detailed Solution

In the reaction we have,


12N2(g)+2H2(g)+12Cl2(g)NH2Cl(s)ΔrS=99.512×1922×130.512×233=374ΔrG=314.5+310×3741000=198.56kJ/mol

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