${CaOCl}_{2} + H_{2} O ⟶ Ca (OH)_{2} + X$
$\underline{X} + {CH}_{3} CHO ⟶ \underline{Y}$
$\underline{Y} + Ca (OH)_{2} ⟶ {CHCl}_{3}$ . What is 'Y'?

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${CH}_{3} CH (OH)_{2}$

${CH}_{2} {Cl}_{2}$

${CCl}_{3} CHO$

${CCl}_{3} {COCH}_{3}$

answer is C.

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Detailed Solution

${CaOCI}_{2} \overset{H_{2} O}{\to} Ca (OH)_{2} + {CI}_{2}$
${CI}_{2} + {CH}_{3} CHO \to {CCI}_{3} - CHO$
${CCI}_{3} CHO \overset{Ca (OH)_{2}}{\to} {CHCI}_{3}$

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