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Capacitance of a capacitor by a thin metal foil is 2µF . If the foil is folded onto itself with a paper of thickness 0.15mm and dielectric constant of paper is 205, width of paper is 40mm then length of foil will be

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0.34 m

1.33 m

13.4 m

4.13 m

answer is D.

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Detailed Solution

$\begin{array}{l} C = \frac{{Kε}_{0} A}{d} = \frac{{Kε}_{0} l \times b}{d} \\ 2 \times 10^{- 6} = \frac{205 \times 8 .85 \times 10^{- 12} \times l \times 40 \times 10^{- 3}}{0 .15 \times 10^{- 3}} \\ l = 4 .13 m \end{array}$

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