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Car B overtakes another car A at a relative speed of 40 ms^-1. How fast will the image of car B appear to move in the mirror of focal length 10 cm fitted in car A, when the car B is 1.9m away from the car A?

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a

4 ms^-1

b

0.2 ms^-1

c

40 ms^-1

d

0.1 ms^-1

answer is D.

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Detailed Solution

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Question Image

Mirror will be convex mirror
$V_{i} = - m^{2} V_{0}$
$V_{i}$ is velocity of image w.r.t mirror
V₀ is velocity of object w.r.t mirror
V₀ = 40m/
$Magnification m = \frac{f}{f - u} = \frac{10}{10 + 190} = \frac{1}{20}$
$v_{1} = - \frac{1}{20^{2}} \times 40 = - 0.1 m / s$

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