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Q.

Car B overtakes another car A at a relative speed of 40ms^-1. How fast will the image of car B appear to move in the mirror of focal length 10cm fitted in car A, when the car B is 1.9m away from the car A

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a

4ms^-1

b

0.2ms^-1

c

40ms^-1

d

0.1ms^-1

answer is D.

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Detailed Solution

Mirror used is convex mirror (rear-view mirror)

$∴ V_{I / m} = - m^{2} V_{O / m}$

Given, $V_{O / m} = 40 m / s$

$m = \frac{f}{f - u} = \frac{10}{10 + 190} = \frac{10}{200}$

$∴ V_{I / m} = - \frac{1}{400} \times 40 = - 0.1 m / s$

$∴ Car will appear to move with speed 0.1 m / s .$

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