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Q.

Carbon atom shows sp2−hybridization in compounds A and B. A decolourises alkaline potassium permanganate solution whereas B cannot decolourise the solution. Then A and B are

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a

Propene and Ethene

b

Benzene and Ethene

c

Ethene and Benzene

answer is B.

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Detailed Solution

Carbon atom in both the compounds shows sp2 hybridization but due to Aromaticity Benzene cannot decolourises the alkaline potassium permanganate solution. 

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