Carboxylic acids are more acidic than Carbonic acid. The following reaction illustrates greater acidic strength of Carboxylic acids over Carbonic acid.
${CH}_{3} C \overset{18}{O} OH + {NaHCO}_{3} \to X + Y + Z;$ X, Y Z in the process are

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${CH}_{3} C \overset{18}{O} ONa; H_{2} O; C {\overset{18}{O}}_{2}$

${CH}_{3} COONa; H_{2} \overset{18}{O}; {CO}_{2}$

${CH}_{3} C \overset{18}{O} ONa; H_{2} O; {CO}_{2}$

${CH}_{3} COONa; H_{2} O; C {\overset{18}{O}}_{2}$

answer is C.

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Detailed Solution

${CH}_{3} - \underset{}{\overset{\underset{| |}{\overset{18}{O}}}{C}} - OH + {NaHCO}_{3} \to {CH}_{3} - \underset{}{\overset{\underset{| |}{\overset{18}{O}}}{C}} - O^{-} {Na}^{+} + H_{2} O + {CO}_{2}; All the {CO}_{2} is liberated from {NaHCO}_{3}$

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