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Q.

Carboxylic acids readily dissolve in aqueous sodium bicarbonate, liberating carbon dioxide. Which one of the following is correct?

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a

Free carboxylic acid and its conjugate base are of comparable stability

b

The conjugate base of the carboxylic acid is more stable than the free carboxylic acid

c

The free carboxylic acid is more stable than its conjugate base

d

The conjugate acid of the carboxylic acid is more stable than the free carboxylic acid

answer is C.

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Detailed Solution

RCOOH+NaHCO3⇌RCOONa+H2O+CO2

or RCOOH+HCO3-⇌RCOO-+H2O+CO2

conjugate base, RCOO- is more stable. That is why equilibrium shifts in forward direction.

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