Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is 8.0 x 10³ NC^-1m². The net charge inside the box is

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zero

$0.07 μC$

$0.08 μC$

$0.16 μC$

answer is B.

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Detailed Solution

$Φ = 8 \cdot 0 \times 10^{3} {NC}^{- 1} m^{2} We know that Φ = q / ε_{0} or q = ε_{0} Φ ∴ q = (8 \cdot 85 \times 10^{- 12}) \times (8 \cdot 0 \times 10^{3}) = 0 .07 \times 10^{- 6} C = 0 .07 μC$

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