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CaS exists in a cubic close packed arrangement of $S^{2 -}$ ions in which $C a^{2 +}$ ions occupy of the available tetrahedral holes. The sum of $C a^{2 +}$ and $S^{2 -}$ ions contained in the unit cell is

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answer is 8.

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Detailed Solution

No.of $S^{2 -} = 8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 4 No . of {Ca}^{2 +} = \frac{1}{2} \times 8 = 4$
Sum of ${Ca}^{2 +} and S^{2 -}$ ions contained in the unit cell = 4+4=8

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