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Q.

Case-Study 2: Read the following passage and answer the questions given below

Three friends Ravi, Raju and Rohit were doing buying and selling of stationery items in a market. The price of per dozens of pens, notebooks and toys are Rupees x, y and z respectively. Ravi purchases 4 dozen of notebooks and sells 2 dozen of pens 5 dozen of toys. Raju purchases 2 dozen of toy and sells 3 dozen of pens and 1 dozen of notebooks. Rohit purchases one dozen of pens and sells 3 dozen of notebooks and one dozen of toys.

In the process, Ravi, Raju and Rohit earn Rs. 1500, Rs. 100 and Rs. 400 respectively.

(i) Write the above information in terms of matrix Algebra.

(ii) What is the total price of one dozen of pens and one dozen of notebooks?

(iii) What is the sale amount of Ravi?

                          OR

 What is the amount of purchases and sales made by all three friends?

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Detailed Solution

(i) From the above information,

 2x-4y+5z=1500 3x+y-2z=100  -x+3y+z=400 2-4531-2-131xyz=1500100400

(ii) From the above matrix assume that,

 A=2-4531-2-131,X=xyz,B=1500100400 X=A-1 B(i)  |A|=2(1+6)+4(3-2)+5(9+1)=680  co-factor matrix A=7-110197-231914, adj A=7193-171910-214 A-1=1|A| adj A A-1=1687193-171910-214From (i)

xyz=1687193-171910-2141500100400

xyz=16810500+1900+1200-1500+700+760015000-200+5600

xyz=16813600680020400

x=200,y=100 and z=300

So, the total price of one dozen of pens and one dozen of notebooks = Rs. 200 + Rs. 100 = Rs. 300.

(iii) For,

The sale amount of Ravi =2x+5z=2×200+5×300=400+1500=1900or 

Now,

The amount of purchases made by all three friends

4y+2z+x=4×100+2×300+200=1200The amount of sales made by all three friends

2x+5z+3x+y+3y+z=5x+4y+6z=5×200+4×100+6×300=3200Therefore, (i) The given information in terms of matrix Algebra it follows,

2-4531-2-131xyz=1500100400

(ii) The total price of one dozen of pens and one dozen of notebooks= Rs. 300 .

(iii) The sale amount of Ravi= Rs. 1900 OR the amount of purchases and sales made by all three friends = Rs. 3200 .

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