CdO has NaCl structures with density 8.27g/cc. If the ionic radius of O2- is 1.24 A0, determine ionic radius of Cd2+.

8.27=4×1286.023×1023a3⇒a=46.8×10−9cm=4.68A0=2[rO22−+rCd2+]⇒rCd2+=1.1A0

CdO has NaCl structures with density 8.27g/cc. If the ionic radius of O2- is 1.24 A0, determine ionic radius of Cd2+.

8.27=4×1286.023×1023a3⇒a=46.8×10−9cm=4.68A0=2[rO22−+rCd2+]⇒rCd2+=1.1A0

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CdO has NaCl structures with density 8.27g/cc. If the ionic radius of O^2- is 1.24 A⁰, determine ionic radius of Cd²⁺.

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$1.9 A^{0}$

$1.5 A^{0}$

$1.3 A^{0}$

$1.1 A^{0}$

answer is B.

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$8.27 = \frac{4 \times 128}{6.023 \times 10^{23} a^{3}}$

$\Rightarrow a = 46.8 \times 10^{- 9} c m = 4.68 A^{0} = 2 [r_{O_{2}^{2 -}} + r_{C d^{2 +}}]$

$\Rightarrow r_{C d^{2 +}} = 1.1 A^{0}$

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CdO has NaCl structures with density 8.27g/cc. If the ionic radius of O2- is 1.24 A0, determine ionic radius of Cd2+.

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CdO has NaCl structures with density 8.27g/cc. If the ionic radius of O^2- is 1.24 A⁰, determine ionic radius of Cd²⁺.